Ferdy Tantowi, David Limanan
Universitas Tarumanagara,
Indonesia
E-mail:
[email protected], [email protected]
KEYWORDS Phytochemicals, DPPH, Alkaloids, Antimitosis,
HPTlC |
ABSTRACT Oxygen is one of the supports
of multicellular life and is necessary for aerobic metabolism. However, the
use of oxygen can produce by-products, one of which is reactive oxygen
species (ROS) which can also increase due to external factors such as
exposure to ionizing rays, and vehicle smoke. When reactive oxygen species
levels� are high, the body can
experience a condition called oxidative stress, which is a condition that can
cause tissue damage. To overcome this, antioxidants are needed, namely
compounds that can donate electrons to free radicals to neutralize their
effects. Antioxidants are divided into endogenous antioxidants and exogenous
antioxidants. Endogenous antioxidants are antioxidants found in the body.
Exogenous antioxidants are antioxidants that come from outside the body.
Because there is an increase in ROS levels due to external influences, an
increase in exogenous antioxidants is needed, one of which is chamomile
flowers. This study evaluated qualitative phytochemical levels using the
Harnborne method, total antioxidant capacity using the Blois method, total
quantitative levels of alkaloids using the Trivedi et al method, BSLT
toxicity using the Meyer method, and fingerprint analysis using HPTLC. The
obtained chamomile flowers are dried and extracted by maceration using
methanol solvent. The test results on chamomile flowers revealed
phytochemical content in the form of alkaloids, betasianin, cardioglycosides,
coumarins, flavonoids, phenols, quinones, saponins, steroids, tepenoids and
tannins. Antioxidant ability 209.27 g/ml; Total alkaloid content of 12.62
g/ml; toxicity 174.39 g/mL; As well as fingerprint analysis chamomile flowers
have active ingredients. Therefore, chamomile flowers can serve as a moderate
antioxidant with antimitotic activity. |
INTRODUCTION
Oxygen
is a molecule that greatly affects chemical reactions in the body. Oxygen has
four known oxidation states. Namely (O2)n, where n=0
(dioxygen, O2);�� n=+1 (dioxygen cation,
O 2+); n=1 (superoxide ion, O 2�-); n=2 (dianion peroxide, O 2�2−).
Superoxide ions are the most common precursors of reactive oxygen species (ROS)
metabolites, and ROS is a highly (Hayyan,
Hashim, & AlNashef, 2016) reactive
oxygen-derived substance such as superoxide and hydrogen peroxide ions. The
formation of ROS can be divided into endogenous, that is, the (Murphy et al.,
2022) result of� by-productsof� mitochondrial metabolism, or exogenous, such
as exposure to ionizing rays, drugs, pollution of the lingkungan
(Cosentino,
Plantamura, Cataldo, & Iorio, 2019). High
levels of ROS in the body can cause oxidative stress.
Oxidative
stress is defined as an imbalance between the production of reactive oxygen
species (ROS) and antioxidants. Which can occur due to an increase in ROS
levels or a decrease in antioxidant levels. Oxidative stress can cause
different types of macromolecular damage in the body such as (Aguiar
et al., 2012)
lipids,
proteins, carbohydrates, and nucleic acids that (Birben,
Sahiner, Sackesen, Erzurum, & Kalayci, 2012) can cause
diseases such as Alzheimer's, cancer, autoimmune. Therefore, antioxidants are
needed that can prevent damage due to oxidative stress.
Antioxidants
can be divided into exogenous and endogenous antioxidants based on their
source, enzymatic and non-enzymatic structure, fat-soluble and fat-insoluble,
intracellular or extracellular in an organism (Evans
& Halliwell, 2001). From Source,
endogenous antioxidants are antioxidants produced in the body, while exogenous
antioxidants are antioxidants obtained from food sources. Together, exogenous
and endogenous antioxidants maintain redox homeostasis such as when
regenerating vitamin E by glutathione, or vitamin C which prevents lipid
peroxidation processes (Bouayed,
Rammal, & Soulimani, 2009).
Chamomile
flowers are flowers described by Hippocrates as a medicinal plant having a wide
variety of benefits, including: fever, inflammation, muscle spasms, menstrual
disorders, ulcers, pain due to rheumatism (Santos-S�nchez,
Salas-Coronado, Villanueva-Ca�ongo, & Hern�ndez-Carlos, 2019). The flowers
contain phenolic compounds, in particular flavonoids apigenin, quercetin, patuletin and luteolin. Phenolic compounds are known to
have potential as antioxidants and antimitosis, thus prompting research to
further find out the antioxidant (Chauhan
& Jaya, 2017) and
antimitotic capabilities� of chamomile
flowers, which are expected to be a source of�
new properties.
RESEARCH METHODS
Manufacture of Chamomile Flower Extract
The sample
obtained is dried. Dry samples are crushed using a blender mixer until they
become powder or simplicia. Then the extract is made
using maceration technique using methanol extract until the top of the simplicia is submerged, the mixture is stirred every
morning and evening. After two days, the extract is accommodated, and into the
maceration tube is added methanol Back, this process is repeated twice. Then
the extract obtained is evaporated using a rotary evaporator.
Research Design
This research is
included in in vitro experimental research and bioassay. Research conducted in
vitro tests consists of phytochemical tests, antioxidant capacity tests, total
alkaloid tests, HPTLC fingerprint analysis and bioassay research in the form of
antimitosis tests with BSLT(BLaws, 1958) (Trivedi,
Patel, Rathnam, & Pundarikakshudu, 2006)
(Meyer
et al., 1982)
Antioxidant
In the antioxidant
examination, DPPH is used as a radical compound used to measure absorbance in a
UV-Vis spectrophotometer. Maximum wavelength examination of DPPH compounds is
carried out, then absorbance data of flower extracts with comparison extracts,
namely vitamin C, is carried out and calculations are carried out in order to
obtain the value of inhibitory concentrate
Determination of the Length of Gelombang Maximum
DPPH with a
concentration of 50 μM was taken as much as 3.5
mL and added 0.5 mL methanol then left in a darkroom for 30 minutes. Then the
solution is read at a wavelength absorbance of 400-800 nm. The solution is
prepared in the form of duplo.
Determination of Standar
Vitamin C
Vitamin C with a
concentration of 2 μg/mL, 4 μg/mL,
6 μg/mL, 8 μg/
mL, and 10 μg/mL is inserted into test tubes of
0.5 mL each and DPPH of 3.5 mL is added. then incubated in a darkroom for 30
minutes and read at maximum wavelength
Penentuan Standar Ekstrak Bunga Chamomile
Chamomile flower
extracts with concentrations of 100 μg/mL, 200 μg/mL, 300 μg/mL, 400 μg/mL, and 500 μg/mL
were put in test tubes of 0.5 each and DPPH of 3.5 mL were added. then
incubated in a darkroom for 30 minutes and read at maximum wavelength
Penentuan Aktivitas Antioksidan Ekstrak Bunga Chamomile
Antioxidant
activity is measured by the absorbance of DPPH radicals inhibited using the
formula:
�Information:
Abs. Control =
radical DPPH uptake of 50 μM at optimal
wavelength
Abs. Sample =
sample uptake in radical DPPH of 50 μM at
optimal wavelength
The antioxidant
concentration value of the sample was calculated using the linear equation Y = aX + b then in the variable y entered the number 50 so as
to produce IC 50 on variable X.
Alkaloid
Manufacture of Larutan
Standar Berberine Chloride
Berberine chloride
with a concentration of 20 μg/mL, 40 μg/mL, 60 μg/mL, 80 μg/mL, and 100 μg/mL
using metaanol solvent. then added 5mL to phosphate
with pH 4.7 and 5mL BCG (bromocresol green).�
The solution is then put into a flask and allowed to stand until two
layers are formed. After that, the bottom layer is accommodated and chloroform
is added up to 10mL so that the final concentrations of 2 μg
/ mL, 4 μg / mL, 6 μg
/ mL, 8 μg / mL, and 10 μg
/ mL are then measured at one of the concentrations and absorbance checks are
carried out at each concentration and the results are made linear line
equations.
Uji Kadar Alkaloid Ekstrak
Bunga C
hamomile
A total of 50 mg
of chamomile flower extract was added with 5mL of phosphate with a pH of 4.7, 3
mL of hydrochloric acid, and 5 mL of BCG. Then the solution is introduced into
the separator flask and homogenized and waited until two layers are formed. The
bottom is then accommodated and chloroform is added to 10mL. The test was
carried out duplo and alkaloid levels were calculated
using the linear line equation of berberine chloride solution
Antimitosis
Hatching of
artemia salina shrimp larvae for 2 x 24 hours was carried out in a tube given
an aerator and illuminated by a lamp. After that, a concentration of chamomile
flower extract was made of 50 μg / mL, 100 μg / mL, 150 μg / mL,
200 μg / mL , and 250 μg / mL, respectively. Then in each tube were inserted
shrimp larvae that had hatched as many as 10 heads and allowed to stand for 24
hours with a light illuminated. This action is carried out with duplo. Then the mortality percentage of shrimp larvae was carried
out at each concentration and a linear line equation curve was made
HPTLC
A total of 10 mg
of chamomile flower extract is dissolved with 1 mL of methanol resulting in a
concentration of 10mg/mL. then a sample application
was carried out on a silica gel plate of 10 μL
with a CAMAG Linomat 5 applicator. In addition, solanesol standards are also used as a terpenoid comparison
in samples. After that, the sample was put into the CAMAG Automatic Development
2 development chamber with N-hexan solvent and ethyl
acetate in a ratio of 1.5:0.5 until a total volme of
35 mL was obtained and left for 30 minutes. After that, the plate is sprayed
with vanillin-phosphoric acid reagent and put in an oven at 100 �C for 10
minutes. Then the plate is removed and checked for documentation with CAMAG TLC
Scanner and CAMAG TLC Visualizer.
RESULTS AND
DISCUSSION
Phytochemical Test
The results of
phytochemical tests on chamomile flower extract showed positive results on
alkaloid compounds, betasianin, cardioglycosides,
coumarins, flavonoids, phenolics, quinones, saponins, steroids, tepenoids, and tannins (Table 1). Plants that contain phytochemism can function as antioxidants
Table
1
Phytochemical
Content
Phytochemicals |
Methods/Reagents |
Chamomile
Flower Extract |
Alkaloid |
Mayer |
+ |
Anthocyanins |
NaOH |
- |
Betasianin |
NaOH |
+ |
Kardioglikosida |
Keller-Kiliani |
+ |
Koumarin |
NaOH |
+ |
Flavonoid |
NaOH |
+ |
Glycosides |
Modified
Borntrager |
- |
Phenolic |
Folin Ciocalteau |
+ |
Kuinon |
H2SO4 |
+ |
Saponin |
Foam
Test |
+ |
Steroid |
Liebermann-Burchard |
+ |
Tepenoid |
Liebermann-Burchard |
+ |
Tannin |
Ferric-Chloride |
+ |
Antioxidant Capacity Test
The maximumDPPH wave event is 516 nm with a maximum absorbance
of 0.546. Then a review of chamomile flower extract and vitamin C standards was
carried out using the wave p. The result is made a curve with the X axis as the
concentration and the Y axis is inhibition. The linear line equation of
vitamin C is Y = 6.934*X + 12.52 with R 2=0.9988, from the linear
equation obtained IC 50 standard vitamin C is 5.4 μg/mL. and the linear line
equation of chamomile flowers is Y = 0.1680*X + 14.61 with R 2 = 0.9801. With
the linear line equation, the IC value of 50 chamomile flower
extract was obtained at 209.27 μg / mL.
Table
2
Vitamin
C Standards
Concentration |
%Inhibition
(%) |
IC50(μg/mL) |
2 |
26,85 |
|
4 |
39,11 |
|
6 |
54,97 |
5,4 |
8 |
67,87 |
|
10 |
81,81 |
|
Figure 1
Vitamin C Standard Curve
Table
3
Antioxidant
Capacity Test of Chamomile Flower Extract
Concentration |
%Inhibition(%) |
IC50(μg/mL) |
100 |
29,396 |
|
200 |
47,161 |
|
300 |
68,498 |
209,27 |
400 |
86,081 |
|
500 |
93,956 |
|
Figure
2
Curve
Chamomile Flower Extract
The DPPH method
was used in this study to test the total antioxidant capacity. Chamomile flower
extract and a comparator standard of vitamin C or ascorbic acid were used to
obtain a comparison of the total antioxidant capacity by calculating an IC
value of50. An IC value of 50 is the concentration required
concentration required to inhibit 50% of DPPH activity. The lower the IC valueof 50 the higher the antioxidant
capacity in the extract. In this study, the IC value of 50 chamomile flower
extract was 209.27 μg / mL and IC 50
ascorbic acid, namely 5.4 μg / mL which makes
chamomile flowers have a moderate antioxidant potential of 101-150 ppm. Based
on these results, it can be concluded that ascorbic acid is a more potent
source of antioxidants. However, excessive consumption of ascorbic acid can
cause indigestion while chamomile flowers can be consumed by people with
indigestion (Sukweenadhi,
Setiawan, Yunita, Kartini, & Avanti, 2020)(Joon
Kyung Lee et al., 2018)
(Albrecht,
M�ller, Schneider, & Stange, 2014)
Alkaloid Test
Berberine
chloride
testing was carried out as a standard alkaloid and chamomile flower extract
with a wavelength of 420 nm to obtain absorbance. Then a linear line equation
is made for the berberine chloride
standard with the X axis as the� concentration and the Y axis as the
absorbance. Then a curve is made for the standard and the linear equation Y =
0.09105*X � 0.09590 with R2 = 0.9857 is obtained. From the linear
equation can be determined the total alkaloid content of chamomile flowers
Table 4
Standar Berberine Chloride
Standard
Levels of Berberine Chloride (μg/mL) |
Absorbansi (λ = 420
nm) |
2 |
0,13 |
4 |
0,22 |
6 |
0,43 |
8 |
0,65 |
10 |
0,83 |
Figure 3
Berberine Chloride Standard Curve
Table 5
Alkaloid Test of Chamomile Flower Extract
Tube |
Absorbance |
Alkaloid
Levels (μg/mL) |
Average
Rate Alkaloid
(μg/mL) |
I |
0,468 |
6,1933 |
6,30 |
II |
0,489 |
6,4239 |
Berberine chloride was used
as a standard in this study to obtain alkaloid levels of chamomile flower
extract. The standard R2 value of berberine chloride is
0.9857 so it has a high level of confidence. The alkaloid level in the
examination was diluted 1: 2, so that the alkaloid content of chamomile flower
extract was obtained at 12.6 μg / mL.
Antimitosis
After
recording deaths at each concentration, a calculation of the percentage of
deaths and a log of larval concentrations were then made. Then a curve is
created where the X axis is the concentration log and the Y axis is the
percentage of deaths. From the curve, the linear line equation Y =
168.7*X - 323.5 and the value R2 = 0.9770 are obtained.
Table 6
Antimitosis Test
Concentration (μg/mL) |
Concentration
Log |
%Death |
LC50
(μg/mL) |
100 |
2 |
17,30 |
174,39 |
150 |
2,18 |
39,13 |
|
200 |
2,3 |
62,22 |
|
250 |
2,4 |
85,41 |
Figure 4
Antimitosis Test
Curve
The
curve results show that the R2 result
in this study is 0.9770 so it has a high level of accuracy and can be trusted.
Based on the linear line equation, the higher the concentration log, the higher
the percentage of larval mortality. The LC value of 50 was obtained,
which is the level needed to kill 50% of the flower extract population is
174.39. The LC value of 50<1000 has antimitosis activity that makes chamomile
flowers have the potential to become antimitosis compounds (Meyer
et al., 1982)
HPTLC
Samples
are documented before and after derivatization. Prior to derivatization, images
were shot at
256 nm, 366 nm, and visible light waves. After
derivatization, documentation was carried out using visible light, as well as densitogram analysis of flower extracts and solanesol standards
Figure 5
Chromatogram of Chamomile Flowers (left)
and Solanesol (right) at 256 nm (A); 366 nm
(B); Visible Light (C); and Visible Light After Derivatization
Figure
6
�Densitograms of
Chamomile Flowers (left) and solanesol (right)
Table
7
Densitogram of
Chamomile Flowers
Peak |
Rf |
High (AU) |
Area (AU) |
Assigned Substance |
1 |
0.04 |
130.2 |
3758.8 |
Unknown |
2 |
0.13 |
99.6 |
2650.1 |
Unknown |
3 |
0.17 |
86.6 |
1572.4 |
Unknown |
4 |
0.23 |
141.5 |
3950.3 |
Unknown |
5 |
0.28 |
166.8 |
5174.8 |
Unknown |
6 |
0.35 |
160.7 |
6727.4 |
Unknown |
7 |
0.47 |
141.7 |
8003.8 |
Unknown |
8 |
0.51 |
142.1 |
7798.5 |
Unknown |
9 |
0.67 |
13.5 |
94.1 |
Unknown |
10 |
0.74 |
15.0 |
252.5 |
Unknown |
11 |
0.76 |
14.2 |
125.0 |
Terpenoid |
Table
8
�Densitogram Solanesol
Peak |
Rf |
High (AU) |
Area (AU) |
Assigned Substance |
1 |
0.40 |
61.6 |
1237.2 |
Solanesol |
There
is a blue band at an Rf value of 0.76 (Figure 5) which indicates that the
extract contains terpenoids. However, when compared with solanesol
with an Rf value of 0.40 (Table 8, Figure 5D) it can be concluded that
chamomile flowers do not contain terpenoid compounds in them. In densitogram testing, 11 peaks were found where 1 peak was
terpenoid (at peak 11) and the other 10 peaks were unidentified active
compounds (Table 7). In another study, it was found that kandugan
bisabolol and chamazulene are derivatives of
terpenoids with an Rf range ranging from 0.75-0.9
CONCLUSION
Chamomile flowers
have moderate antioxidant activity with an IC value of 50 209.27 μg / mL, the total alkaloid content with berberine
chloride comparison standards is 12.62 μg / mL,
the antimitotic activity of flowers gets an LC value of 50 of 174.39 so that it
has antimitotic activity, and examination using HPTLC found the presence of 11
active compounds of which one is terpenoid.
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Copyright holders:
Ferdy Tantowi,
David Limanan (2023)
First publication right:
Devotion - Journal of Research and Community Service
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